Australia beat India by 8 wickets in the first Test at Adelaide

Australian team wins Adelaide Test match

Australia beat India by 8 wickets in the first Test at Adelaide. In the 2nd innings of the match, India batted poorly for just 36 runs.

India scored 244 and Australia 191 in the first innings of the first Test. At the end of the second day's play, the Indian team had scored 9 runs for the loss of one wicket in the second innings. In this situation, the Australian bowlers shocked the Indian team which started the third day's play today.

The Indian team lost 9 wickets for 36 runs. The Indian team ended the second innings with 36 runs as Mohammad Sami was injured after being run out for a run. Pat Cummins took 4 wickets and Jose Hazlewood took 5 wickets.

Three of the Indian batsmen were bowled out for nothing. Others did not cross single-digit runs. This is the lowest number of wickets taken by an Indian team in a Test match innings. The previous lowest score was 42 in a match against England in 1974.

Playing the second innings with an easy target of 90, the Australians reached the target, losing only 2 wickets. Joe Burns of that team was unbeaten on 51 runs.

The fans were shocked when the Indian team curled in the lowest number of runs and the Australian team won the match in three days.